Transform XML using XSLT

[sicarioseth]

Hi,

I am new with Mirth and I want to know how can I transform an XML in other XML using a XSLT.

I have read that it is possible but I do not know how

Thanks for answers.

[albertosaez]

Re:Transform XML using XSLT

It's not easy. You could use the Java objetc to made the tranformation.

It's not impossible, but you can do with JS more, and clearer.

[Alessandro]

Re:Transform XML using XSLT

Do you have any example how i could do it with javascript in mirth? I have searched the internet, but i could not find a suitable solution for that.

i found this :

try {

    XSLTProcessor processor = XSLTProcessorFactory.getProcessor(); 
       
    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    
    processor.process(new XSLTInputSource("games.xml"«»),
                      new XSLTInputSource("games.xsl"«»),
                    new XSLTResultTarget(bos));

    out.println(bos);
    
} catch (Exception ex) {
    out.println(ex);
}

but that don't seems te be work

Alessandro

Post edited by: Alessandro, at: 01/16/2008 03:19

[albertosaez]

Re:Transform XML using XSLT

What's the error you're getting ?

[Alessandro]

Re:Transform XML using XSLT

Hi I changed the code to

XSLTProcessor processor = XSLTProcessorFactory.getProcessor(); 
ByteArrayOutputStream bos = new ByteArrayOutputStream();
processor.process(new XSLTInputSource(msg), new XSLTInputSource("[url]http://localhost/mirth.xsl"«»[/url]), new XSLTResultTarget(bos));
channelMap.put(toXSL,bos)

from the mirth valiation I get the error :

Error on line 1: mising ; before statement (850f3251-df69-4a94-b8a0-eaf51bc97519#1)

After that i change the code to :

processor = XSLTProcessorFactory.getProcessor(); 
bos = new ByteArrayOutputStream();
processor.process(new XSLTInputSource(msg), new XSLTInputSource("[url]http://localhost/mirth.xsl"«»[/url]), new XSLTResultTarget(bos));
channelMap.put(toXSL,bos)

And i get the error

ReferenceError: "XSLTProcessorFactory" is not defined.

Post edited by: Alessandro, at: 01/16/2008 11:29

[Alessandro]

Re:Transform XML using XSLT

Hello,

I have search the forum and the internet. I thing i need to import some xalan functions.

import org.apache.xalan.xslt.XSLTProcessor

http://xml.apache.org/xalan-j/samples.html

But xalan is not installed. Can i dowloand xalan.jar and put it in the lib folder or do i need more?

[dans]

Re:Transform XML using XSLT

Hi Alessandro,

I emailed you this code snippet but I will post here in case someone else has the same problem. Here is the code I used to do the xslt transformation:

importPackage(Packages.javax.xml.transform);
importPackage(Packages.javax.xml.transform.stream) ;
var tFactory = TransformerFactory.newInstance();
var xslSource = new StreamSource("c:\\ORU-R01.xsl");
var transformer = tFactory.newTransformer( xslSource );
var bos = new java.io.ByteArrayOutputStream();
var sbis = new java.io.StringBufferInputStream(msg);
transformer.transform( new StreamSource(sbis),new StreamResult( bos ));
msg = bos.toString();

Hope that helps.

[fmason]

Re:Transform XML using XSLT

I am brand new to xslt and am wanting to do something like this but am finding resources to be inadequate. Can someone point me to a good tutorial on xslt that is focused on xml to xml transformation?

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:«»stylesheet version="1.0" xmlns:«»xsl="[url]http://www.w3.org/1999/XSL/Transform">[/url]

   <xsl:template match="/">

      <xsl:for-each select="sample">
         **change name of sample to aloquot**
      </xsl:for-each>
   </xsl:template>
</xsl:«»stylesheet>

the above example was borrowed from w3c schools

Post edited by: fmason, at: 12/16/2008 14:42

[Alessandro]

Re:Transform XML using XSLT

Take a look on Mirth 1.8. As far as i read the specs, it sould have build in XSLT transform support

http://www.mirthproject.org/communit...owse/MIRTH-842 - Add XSLT transformer support


Alessandro

[fmason]

Re:Transform XML using XSLT

Go Mirth 1.8.0!!

So this is essentially a best practices question but includes some nuts and bolts details

I make a REST call and get a response - I want to transform that response - it seems to me that the most appropriate place to do that is in at postprocessor step. In Mirth however, as of yet, there doesn't appear to be a transform step there. I can do it manually like I was about to in 1.7.1, but it seems like I should be able to take advantage of the built in xslt support - that would be a much cleaner way to do this.

I am also still struggling with the purpose and use of a number of the provided functions

responseMap.get('')
responseMap.put(connector, ResponseFactory.getSuccessResponse('message'))

These two for example seem like they would do a lot of what I am trying to accomplish. I don't know however, how to get a reference to my connector. There doesn't appear to be an id like there is with the channels, do I just need to dig through the source code and figure that out or is there more documentations somewhere?

I have found this, but am a little confused about precisely what it is suppose to do
http://www.mirthproject.org/index.ph...7&catid=2#5117

This for example

channelMap.put('SoapResponseXML', strXMLData);

looks really great, but I am not sure what the first parameter does.

http://www.mirthproject.org/index.ph...4&catid=2#7204

this one looks better - trying it now

Fieran

Post edited by: fmason, at: 12/17/2008 08:11

Post edited by: fmason, at: 12/17/2008 08:43

Post edited by: fmason, at: 12/17/2008 08:52

Post edited by: fmason, at: 12/17/2008 11:15

[fmason]

solution

So this accomplished what I wanted - I hope someone else can use it too.
Set up -
channel

inbound connector => httpListener
Respond from myHTTPSender
outbound connectors => httpSender, javascriptWriter

javascriptWritter code:

importPackage(Packages.javax.xml.transform);
importPackage(Packages.javax.xml.transform.stream);

java.lang.System.out.println('Channel B - Transformer - response:\n' + responseMap.get('myHTTPSender').getMessage());
var tFactory = TransformerFactory.newInstance();
var xslSource = new StreamSource("path to xsl"«»);
var transformer = tFactory.newTransformer( xslSource );
var bos = new java.io.ByteArrayOutputStream();
var sbis = new java.io.StringBufferInputStream(responseMap.get('myHTTPSender').getMessage());

transformer.transform( new StreamSource(sbis),new StreamResult( bos ));

java.lang.System.out.println('Channel B - Transformer - transformed response:\n' + bos.toString());

responseMap.get('myHTTPSender').setMessage( bos.toString() );

[geo]

XSLT Problem

importPackage(Packages.javax.xml.transform);
importPackage(Packages.javax.xml.transform.stream) ;
var tFactory = TransformerFactory.newInstance();
var xslSource = new StreamSource("c:\\ORU-R01.xsl");
var transformer = tFactory.newTransformer( xslSource );
var bos = new java.io.ByteArrayOutputStream();
var sbis = new java.io.StringBufferInputStream(msg);
transformer.transform( new StreamSource(sbis),new StreamResult( bos ));
msg = bos.toString();


Hello

I need to get output file by adding xsl style on my given input xml file
What is the steps which I have to follow
I have input xml file and XLS file
When I manually combine these two with "<?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?>" these kind of include it will work
What Mirth can do for achieving this

Any help wuld be appreciated

Geo