1.5 Regular Expressions

[mulaa]

Hi,

Just wondering if someone give an example of how to use the regular expression form in the transformer. I need to replace a ' (single quote) with " " (null).

What I have
Regular expression: '
ReplaceWith: ""

Any help is appreciated.

[brendanh]

Re:1.5 Regular Expressions

You might want to do this in the preprocessor script if you are trying to remove all 's from your message. I think it is something like:

return message.replace(/\\u002c/g, "");

If that doesn't work, Chris would know how to answer this better than me (he loves regular expressions).

Post edited by: brendanh, at: 05/30/2007 15:52

[chrisl]

Re:1.5 Regular Expressions

Regular Expression:

/'/g

Replace with:

""

[brendanh]

Re:1.5 Regular Expressions

That won't compile buddy.

[chrisl]

Re:1.5 Regular Expressions

Try:

/\\\\'/g

Post edited by: chrisl, at: 05/31/2007 02:21

[mulaa]

Re:1.5 Regular Expressions

I couldn't get that to work, it doesn't like

/\\\\'/g

,

/\\'/g

is accepted but does not remove the '.

I used the following in the preprocessing script and it worked:

var reg = new RegExp();
reg.compile("'", "g"«»);
return message.replace(reg,(""«»));

Post edited by: mulaa, at: 05/31/2007 14:03